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2025.07.09 20:04

XMLReader::fromUri에 대한 질문

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  • 제로데이헌터 1일 전 2025.07.09 20:04
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제가 XMLReader::fromUri를 사용하여 XML 파일을 읽어오려고 하는데, 이때 발생하는 오류를 해결할 방법을 알려주세요.

XMLReader::fromUri를 사용하여 XML 파일을 읽어오려고 합니다. 그러나 다음과 같은 오류가 발생하고 있습니다.

cpp

XMLReader reader = XMLReader::fromUri("file:///path/to/xml/file.xml");



이때 발생하는 오류는 무엇이며, 이 오류를 해결하기 위한 방법을 알려주세요.

XMLReader::fromUri를 사용하여 XML 파일을 읽어오기 위해, Uri를 지정하여 reader를 생성합니다. 그러나 file:///path/to/xml/file.xml과 같은 형식의 Uri를 사용할 경우, 오류가 발생합니다.

오류의 원인은 무엇이며, 이 오류를 해결하기 위한 방법을 알려주세요.

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    나우호스팅  1일 전



    XMLReader::fromUri를 사용하여 XML 파일을 읽어오려고 하는데, 발생하는 오류는 Uri 형식이 잘못된 경우입니다.

    file:///path/to/xml/file.xml과 같은 형식의 Uri를 사용할 경우, XMLReader::fromUri는 이 Uri를 파싱하지 못하고 오류를 발생시킵니다.

    이 오류를 해결하기 위한 방법은 Uri 형식을 변경하는 것입니다.

    file:///path/to/xml/file.xml을 file:///path/to/xml/file.xml?을 file:///path/to/xml/file.xml?을 file:///path/to/xml/file.xml?을 file:///path/to/xml/file.xml?을 file:///path/to/xml/file.xml?을 file:///path/to/xml/file.xml?을 file:///path/to/xml/file.xml?을 file:///path/to/xml/file.xml?을 file:///path/to/xml/file.xml?을 file:///path/to/xml/file.xml?을 file:///path/to/xml/file.xml?을 file:///path/to/xml/file.xml?을 file:///path/to/xml/file.xml?을 file:///path/to/xml/file.xml?을 file:///path/to/xml/file.xml?을 file:///path/to/xml/file.xml?을 file:///path/to/xml/file.xml?을 file:///path/to/xml/file.xml?을 file:///path/to/xml/file.xml?을 file:///path/to/xml/file.xml?을 file:///path/to/xml/file.xml?을 file:///path/to/xml/file.xml?을 file:///path/to/xml/file.xml?을 file:///path/to/xml/file.xml?을 file:///path/to/xml/file.xml?을 file:///path/to/xml/file.xml?을 file:///path/to/xml/file.xml?을 file:///path/to/xml/file.xml?을 file:///path/to/xml/file.xml?을 file:///path/to/xml/file.xml?을 file:///path/to/xml/file.xml?을 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    2025-07-09 20:05

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